مقدار مجهول را بیابید.
16
\(2\sqrt 2 \)
4
\(4\sqrt 2 \)
\(\begin{array}{l}{x^2} + {x^2} = {\left( {\sqrt {32} } \right)^2}\,\, \Rightarrow \,\,2{x^2} = 32\\\\ \Rightarrow {x^2} = 16\,\, \Rightarrow \,\,x = 4\end{array}\)