گام به گام کاردرکلاس صفحه 88 درس 7 ریاضی هفتم (توان و جذر)

\( - {3^2} = - (3 \times 3) = - 9\)

\({\left( { - 5} \right)^2} = \left( { - 5} \right) \times \left( { - 5} \right) = 25\)

\( - {1^5} = - {(1)^5} = - 1\)

\(\begin{array}{l}{\left( { - 1} \right)^5} = \\\\\left( { - 1} \right) \times \left( { - 1} \right) \times \left( { - 1} \right) \times \left( { - 1} \right) \times \left( { - 1} \right) = - 1\end{array}\)

\({\left( { - 1} \right)^4} = \left( { - 1} \right) \times \left( { - 1} \right) \times \left( { - 1} \right) \times \left( { - 1} \right) = 1\)

\( - {1^4} = - {(1)^4} = - 1\)

\({7^0} = 1\)

\({\left( {\frac{2}{7}} \right)^0} = 1\)

\({\left( { - 9} \right)^0} = 1\)

\({0^5} + 1/{1^0} = 0 + 1 = 1\)

\(4 + {2^0} = 4 + 1 = 5\)

\( - {1^5} = - {(1)^5} = - 1\)

\({2^3} = 2 \times 2 \times 2 = 8\)

\({\left( { - 2} \right)^3} = \left( { - 2} \right) \times \left( { - 2} \right) \times \left( { - 2} \right) = - 8\)

\({5^0} = 1\)

\(\begin{array}{l}{2^0}\;\bigcirc \;{2^1}\\\\\left\{ \begin{array}{l}{2^0} = 1\\\\{2^1} = 2\end{array} \right. \Rightarrow {2^0}\; < \;{2^1}\end{array}\)

\(\begin{array}{l}{7^0}\;\bigcirc \;{7^1}\\\\\left\{ \begin{array}{l}{7^0} = 1\\\\{7^1} = 7\end{array} \right. \Rightarrow {7^0}\; < \;{7^1}\end{array}\)

\(\begin{array}{l}{\left( {\frac{3}{5}} \right)^2}\;\bigcirc \;{2^0}\\\\\left\{ \begin{array}{l}{\left( {\frac{3}{5}} \right)^2} = \frac{9}{{25}}\\\\{2^0} = 1\end{array} \right. \Rightarrow {\left( {\frac{3}{5}} \right)^2}\; < \;{2^0}\end{array}\)

\(\left( { - 2} \right)\;\bigcirc \;{\left( { - 2} \right)^1} \Rightarrow \left( { - 2} \right)\; = \;{\left( { - 2} \right)^1}\)