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١ تساوی های زیر را با استفاده از اتحاد مناسب کامل کنید.
1 \((1 + a)(1 - a) = 1 - .............\)
2 \((2a + 5)(2a - 5) = ............. - 25 \)
3 \((t + .............)(t - .............) = {t^2} - 9\)
4 \({(a - b - c)^2} = {a^2} + {b^2} + .............\)
1 \((1 + a)(1 - a) = 1 - {a^2}\)
2 \((2a + 5)(2a - 5) = 4{a^2} - 25\)
3 \((t + 3)(t - 3) = {t^2} - 9\)
4 \({(a - b - c)^2} = {a^2} + {b^2} + {c^2} - 2ab - 2ac + 2bc\)
٢ حاصل عبارت های زیر را مانند نمونه با استفاده از اتحاد مزدوج به دست آورید.
1
\((10 - x)(x + 10) = (10 - x)(10 + x) = 100 - {x^2}\)
2
\(\begin{array}{l}( - y - 2z)( - 2z + y) = (.......... - y)( - 2z + y) = \\\\4{z^2} - ...........\end{array}\)
3
\(( - 7y + t)(t + 7y) = \)
4
\(( - 4y - 2z)(2z - 4y) = \)
5
\(\begin{array}{l}(x - 2y + 5)(x + 2y - 5) = \\\\\left[ {x - (2y - 5)} \right]\left[ {x + (2y - 5)} \right] = \end{array} \)
1
\((10 - x)(x + 10) = (10 - x)(10 + x) = 100 - {x^2} \)
2
\(\begin{array}{l}( - y - 2z)( - 2z + y) = ( - 2z - y)( - 2z + y) = \\\\4{z^2} - {y^2}\end{array}\)
3
\(\begin{array}{l}( - 7y + t)(t + 7y) = (t - 7y)(t + 7y) = \\\\{t^2} - 14{y^2}\end{array}\)
4
\(\begin{array}{l}( - 4y - 2z)(2z - 4y) = ( - 4y - 2z)( - 4y + 2z) = \\\\16{y^2} - 4{z^2}\end{array}\)
5
\(\begin{array}{l}(x - 2y + 5)(x + 2y - 5) = \\\\\left[ {x - (2y - 5)} \right]\left[ {x + (2y - 5)} \right] = \\\\{x^2} - {(2y - 5)^2} = {x^2} - 4{y^2} + 20y - 25\end{array}\)
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