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با توجّه به ضابطهٔ هر تابع و مانند نمونه، مجموعهٔ مقادیر یا بُرد هر تابع را مشخص کنید.
\(\begin{array}{*{20}{l}}{\begin{array}{*{20}{l}}{f:A \to B}\\{f(x) = 2{x^2} + 1}\end{array}}\end{array}\,\,\,\,\,,\,\,\,\,\,A = \left\{ { - 1\,,\,\sqrt 2 \,,\,2\,,\,1\,,\,0\,,\,\frac{1}{2}} \right\}\)
\(\begin{array}{*{20}{l}}{\begin{array}{*{20}{l}}{f:A \to B}\\{f(x) = \sqrt {x + 1} - 1}\end{array}}\end{array}\,\,\,\,\,,\,\,\,\,\,A = \left\{ {0\,,\, - 1\,,\,8\,,\,3\,,\,2} \right\}\) الف
\(\begin{array}{*{20}{l}}{\begin{array}{*{20}{l}}{f:A \to B}\\{f(x) = \frac{{x + 1}}{{x - 2}}}\end{array}}\end{array}\,\,\,\,\,,\,\,\,\,\,A = \left\{ { - 2\,,\,0\,,\,1\,,\,\sqrt 2 \,,\,\frac{1}{2}} \right\}\) ب
\(\begin{array}{*{20}{l}}{\begin{array}{*{20}{l}}{f:A \to B}\\{f(x) = \sqrt {x + 1} - 1}\end{array}}\end{array}\,\,\,\,\,,\,\,\,\,\,A = \left\{ {0\,,\, - 1\,,\,8\,,\,3\,,\,2} \right\}\) الف
\(\begin{array}{*{20}{l}}{\begin{array}{*{20}{l}}{f:A \to B}\\{f(x) = \frac{{x + 1}}{{x - 2}}}\end{array}}\end{array}\,\,\,\,\,,\,\,\,\,\,A = \left\{ { - 2\,,\,0\,,\,1\,,\,\sqrt 2 \,,\,\frac{1}{2}} \right\}\) ب
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