درمثلث قائم الزاویهٔ مقابل در هر مورد سعی کنید با ساده ترین روش مقادیر خواسته شده را به دست آورید.

1 \(e = ?\mathop {}\nolimits_{} \mathop {}\nolimits_{} d = 7\mathop {}\nolimits_{} \mathop {}\nolimits_{} h = 5\)
\({h^2} = d \times e \Rightarrow 25 = 7 \times e \Rightarrow e = \frac{{25}}{7}\)
2 \(c = ?\mathop {}\nolimits_{} \mathop {}\nolimits_{} b = ?\mathop {}\nolimits_{} \mathop {}\nolimits_{} e = 3\mathop {}\nolimits_{} \mathop {}\nolimits_{} d = 5\)
\(\begin{array}{l}{c^2} = d\left( {d + e} \right)\\\\ \Rightarrow {c^2} = 5\left( {5 + 3} \right) = 40\\\\ \Rightarrow c = 2\sqrt {10} \\\\{b^2} = e\left( {d + e} \right)\\\\ \Rightarrow {b^2} = 3\left( {5 + 3} \right) = 24\\\\ \Rightarrow b = 2\sqrt 6 \end{array}\)
3 \(h = ?\mathop {}\nolimits_{} \mathop {}\nolimits_{} b = 6\mathop {}\nolimits_{} \mathop {}\nolimits_{} c = 8\)
\(\begin{array}{l}BC = \sqrt {{6^2} + {8^2}} = 10\\\\b \times c = h \times BC\\\\ \Rightarrow 6 \times 8 = 10 \times h \Rightarrow h = \frac{{48}}{{10}}\end{array}\)