برای تابع \(\left\{ \begin{array}{l}f:\left[ {0\;,\;\frac{1}{3}} \right] \to \;\left[ {0\;,\;\frac{1}{9}} \right]\\f\left( x \right) = {x^2}\end{array} \right.\;\) کدام یک از نمایش های زیر نیز قابل قبول است؟
الف \(\left\{ \begin{array}{l}f:R \to R\\f\left( x \right) = {x^2}\end{array} \right.\)
ب \(\left\{ \begin{array}{l}f:\left[ {0\;,\;\frac{1}{3}} \right] \to \left[ {0\;,\;\infty } \right]\\f\left( x \right) = {x^2}\end{array} \right.\)
پ \(\left\{ \begin{array}{l}f:R \to \left[ {0\;,\;\frac{1}{9}} \right]\\f\left( x \right) = x\end{array} \right.\)
ت \(\left\{ \begin{array}{l}f:\left[ {0\;,\;\frac{1}{3}} \right] \to R\\f\left( x \right) = {x^2}\end{array} \right.\)
الف \(\left\{ \begin{array}{l}f:R \to R\\f\left( x \right) = {x^2}\end{array} \right.\)
نادرست
ب \(\left\{ \begin{array}{l}f:\left[ {0\;,\;\frac{1}{3}} \right] \to \left[ {0\;,\;\infty } \right]\\f\left( x \right) = {x^2}\end{array} \right.\)
درست
پ \(\left\{ \begin{array}{l}f:R \to \left[ {0\;,\;\frac{1}{9}} \right]\\f\left( x \right) = x\end{array} \right.\)
نادرست
ت \(\left\{ \begin{array}{l}f:\left[ {0\;,\;\frac{1}{3}} \right] \to R\\f\left( x \right) = {x^2}\end{array} \right.\)
درست